MATH SOLVE

4 months ago

Q:
# If f(x) = x2 – 2x and g(x) = 6x + 4, for which value of x does (f + g)(x) = 0?–4–224

Accepted Solution

A:

f(x) = x^2 - 2x

g(x) = 6x + 4

(f + g)(x)......so we add them

x^2 - 2x + 6x + 4 = 0

x^2 + 4x + 4 = 0

(x + 2)(x + 2) = 0

(x + 2)^2 = 0

x + 2 = 0

x = -2 <====

g(x) = 6x + 4

(f + g)(x)......so we add them

x^2 - 2x + 6x + 4 = 0

x^2 + 4x + 4 = 0

(x + 2)(x + 2) = 0

(x + 2)^2 = 0

x + 2 = 0

x = -2 <====