MATH SOLVE

4 months ago

Q:
# Identify the factor terms by grouping: 5x3 – 4x2 + 20x – 16

Accepted Solution

A:

5x3-4x2-20x+16=0 Three solutions were found : x = 4/5 = 0.800 x = 2 x = -2Reformatting the input :Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2". 1 more similar replacement(s).

Step by step solution :Step 1 :Equation at the end of step 1 : (((5 • (x3)) - 22x2) - 20x) + 16 = 0 Step 2 :Equation at the end of step 2 : ((5x3 - 22x2) - 20x) + 16 = 0 Step 3 :Checking for a perfect cube : 3.1 5x3-4x2-20x+16 is not a perfect cube

Trying to factor by pulling out : 3.2 Factoring: 5x3-4x2-20x+16

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 5x3+16 Group 2: -4x2-20x

Pull out from each group separately :

Group 1: (5x3+16) • (1)Group 2: (x+5) • (-4x)

I hope it helps

(1): "x2" was replaced by "x^2". 1 more similar replacement(s).

Step by step solution :Step 1 :Equation at the end of step 1 : (((5 • (x3)) - 22x2) - 20x) + 16 = 0 Step 2 :Equation at the end of step 2 : ((5x3 - 22x2) - 20x) + 16 = 0 Step 3 :Checking for a perfect cube : 3.1 5x3-4x2-20x+16 is not a perfect cube

Trying to factor by pulling out : 3.2 Factoring: 5x3-4x2-20x+16

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 5x3+16 Group 2: -4x2-20x

Pull out from each group separately :

Group 1: (5x3+16) • (1)Group 2: (x+5) • (-4x)

I hope it helps